Solve and find value of y.
3x2−5y3=−2 ; x2+y2=136
y=5119
3x2 - 5y3 = -2
LCM of 2 and 3 is 6. Multiply by 6 on both sides
9x−10y=−12 -------------(1)
x2+y2=136
LCM is 6. Multiply by 6 on both sides
3x+3y=13 --------------(2)
Multiply equation (2) by 3 to eliminate x ; so we get,
9x+9y=39...............(3)
Subtract (3) from (1) we have
−19y=−51⇒y=5119
Substitute this in one of the equation and we get
x=10[5119−129]=28219×9=943×19=9457
⇒x=9457