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Question

Solve and find value of y.

3x25y3=2 ; x2+y2=136


A

y=11754

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B

y=5119

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C

y=5719

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D

y=9457

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Solution

The correct option is B

y=5119


3x2 - 5y3 = -2

LCM of 2 and 3 is 6. Multiply by 6 on both sides

9x10y=12 -------------(1)

x2+y2=136

LCM is 6. Multiply by 6 on both sides

3x+3y=13 --------------(2)

Multiply equation (2) by 3 to eliminate x ; so we get,

9x+9y=39...............(3)

Subtract (3) from (1) we have

19y=51y=5119

Substitute this in one of the equation and we get

x=10[5119129]=28219×9=943×19=9457

x=9457


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