Question

Solve
$b=\frac{1}{\left(1+\frac{3}{2}\times \frac{8}{3}\right)+2}\times \frac{3}{2}$

Answer 1

$b=\frac{1}{(1+\frac{3}{2}\times \frac{8}{3})+2}\times \frac{3}{2}$

$=\frac{1}{(1+4)+2}\times \frac{3}{2}$

$=\frac{1}{5+2}\times \frac{3}{2}$

$=\frac{1}{7}\times \frac{3}{2}=\frac{3}{14}$