Solve- x-1log39-3- 1-

x 1log _39 3=1 x 12 3=1 x 1= 1 x=0 ...

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Fundamental Theorem of Arithmetic

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Question

Solve: $\frac{x - 1}{{log}_{3} (9) - 3} = 1$ .

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Solution

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{log}_{2} x = \frac{1}{2}

{log}_{\frac{1}{5}} x = 3

{log}_{3} y = - 2

{log}_{x} 125 \sqrt{5} = 7

{log}_{x} 0.001 = - 3

x + 2 {log}_{27} 9 = 0

{log}_{3} (\sqrt{x} + | \sqrt{x} - 1 |) = {log}_{9} (4 \sqrt{x} - 3 + 4 | \sqrt{x} - 1 |)

{log}_{x} 3 + {log}_{3} x = {log}_{\sqrt{3}} x + {log}_{3} \sqrt{x} + \frac{1}{2}

{log}_{3} ({log}_{2} x) = 1

{log}_{2} [{log}_{3} ({log}_{2} x)] = 1

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