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Question

Solve 2cos1x=sin1(2x1x2).

A
xϵ[1/1,1]
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B
x[12,12]
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C
x[22,12]
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D
x[32,12]
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Solution

The correct option is B x[12,12]
If 12θ12 then 2sin1θ=sin1(2θ1θ2)
2cos1x=sin1(2x1x2)2cos1x=2sin1x
x[12,12]

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