Question

Solve $x={125}^{\frac{-1}{3}}$ and Find the value of $10x$.

Answer 1

$x={\left(125\right)}^{\frac{-1}{3}}\Rightarrow x={\left(5^3\right)}^{\frac{-1}{3}}\Rightarrow x={\left(5\right)}^{-1}\Rightarrow x=\frac{1}{5}$

$\therefore 10x=2$