Solve each equation using trial and error method
n4=2
Solving equation using trial and error method
As we know 44=1 and we need 2 here so nshould be greater than 4
n
LHS
RHS
5
n4=54=1.25
2
LHS≠RHS
6
n4=64=1.5
7
n4=74=1.75
8
n4=84=2
LHS=RHS
From the table, we find that LHS=RHS when n=8
Hence, the solution of given equation is n=8
4z+2=10
5b+6=11
7x+4=11