Question

Solve each of the following equations and also verify your solution :

$\frac{7}{x}+35=\frac{1}{10}$

Answer 1

$\frac{7}{x}+35=\frac{1}{10}$
Substracting 35 from both sides,
$\frac{7}{x}+35-35=\frac{1}{10}-35$
$\frac{7}{x}=\frac{1-350}{10}$
$\Rightarrow \frac{7}{x}=\frac{-349}{10}$
$\Rightarrow -349\times x=7\times 10$
(By cross multiplication)
$\Rightarrow x=\frac{7\times 10}{-349}=\frac{70}{-349}=\frac{-70}{349}$
$\therefore x=\frac{-70}{349}$
$L.H.S.=\frac{7}{x}+35$
$==\frac{\frac{7}{-70}}{349}+35=\frac{-7\times 349}{70}+35=\frac{-349}{10}+35=\frac{-349+350}{10}=\frac{1}{10}=R.H.S.$