wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve each of the following equations by using the method of completing the square:

2x2-3x-22=0

Open in App
Solution

2x2-3x-22=02x2-32x-4=0 Multiplying both sides by 22x2-32x=42x2-2×2x×32+322=4+322 Adding 322 on both sides
2x-322=4+94=254=5222x-32=±52 Taking square root on both sides2x-32=52 or 2x-32=-522x=52+32=82=4 or 2x=-52+32=-22=-1
x=42=22 or x=-12=-22
Hence, 22 and -22 are the roots of the given equation.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon