We have, √2x+9−(2x−7)=0
√2x+9=(2x−7)
On squaring both sides
(√6x+7)2=(2x−7)2
⇒ 6x+7=4x2+49−28x
⇒ 4x2+42−34x=0
⇒ 2x2−17x+21=0
⇒ 2x2−14x−3x+21=0
⇒ 2x (x−7)−3 (x−7)=0
⇒ (2x−3) (x−7)=0
⇒ x=32 or 7
∴ x=7 (as x=3/2 doesn't satisfy the given equation)
N.B. : always check if the original equation is satisfied by all the values you got