Solve for Y.
3√6125×(Y)=35
7
Here in expression 3√6125×(Y)=35,
we can see thatcube root of 6125×(Y) is equal to 35, which implies cube of 35 is equal to 6125×(Y).
Hence, 6125×(Y) = 353
So, 6125×(Y)=42875
Y=428756125
Y=7
Alternate Solution,
By Prime factorization of 6125 , we get 6125=5×5×5×7×7
Hence 3√6125=5×5×5×7×7×(Y)=35
To get a perfect cube , we need to have the triplet of the prime factor .
Given that cube root of 6125 is multiplied by a number to get the perfect cube .
In the factorization , we have 5 forming a triplet but not 7 , Hence when we multiply 6125 and 7 , it becomes a perfect cube .
3√6125=5×5×5×7×7×(Y) = 3√6125=5×5×5×7×7×(7)=35
∴Y=7