Question

Solve:
$\left(x-6\right)\left(x+7\right)=\left(x+3\right)\left(x-11\right)$

Answer 1

Given :- $(x-6)(x+7)=(x+3)(x-11)$

$\Rightarrow x^2+x-42=x^2-8x-33$

$\Rightarrow 8x+x=42-33$

$\Rightarrow 9x=9$

$\Rightarrow x=1$