√3x2+10x+7√3=0
x2+10√3+7= 0
x2+10√3=-7
Third term = (12×coefficientofx)2
= (12×10√3)2
= (5√3)2
=253
Therefore,
x2+10√3 + 253=-7 + 253.. (adding to both sides)
x2+10√3 + 253 = 43.
( x - 5√3.) =± 2√3 ... (taking square roots)
Hence,
x = 7√3 ,√3