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Question

# Solve the following pairs of linear (simultaneous) equation by the method of elimination: 8x+5y=9, 3x+2y=4

A
x=1 and y=7
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B
x=3 and y=4
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C
x=2 and y=5
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D
x=0 and y=1
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Solution

## The correct option is C x=−2 and y=5Multiply the equation 8x+5y=9 by 3 and equation 3x+2y=4 by 8 to make the coefficients of x equal. Then we get the equations:24x+15y=27.........(1)24x+16y=32.........(2)Subtract Equation (1) from Equation (2) to eliminate x, because the coefficients of x are the same. So, we get(24x−24x)+(16y−15y)=32−27i.e. y=5Substituting this value of y in the equation 8x+5y=9, we get8x+25=9i.e. 8x=−16i.e. x=−2Hence, the solution of the equations is x=−2,y=5.

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