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Question

Solve the following quadratic equation by factorization method: [2 MARKS]

a2b2x2+b2xa2x1=0

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Solution

Concept :1 Mark
Application : 1 Mark

(i) We have,

a2b2x2+b2xa2x1=0

(a2b2x2+b2x)(a2x+1)=0 [Grouping]

b2x(a2x+1)1(a2x+1)=0

(a2x+1)(b2x1)=0

a2x+1=0, b2x1=0

a2x=1,b2x=1

x=1a2,x=1b2

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