Question

Solve the following system of equations by using the cross-multiplication method:
$2x+5y=1;2x+3y-3=0$

Answer 1

Given system of equation:-

$2x+5y-1=0$

$2x+3y-3=0$

By using cross multiplication method,

$\frac{x}{-15+3}=\frac{y}{-2+6}=\frac{1}{6-10}$

$\Rightarrow \frac{x}{-12}=\frac{y}{4}=\frac{1}{-4}$

$\Rightarrow \frac{x}{-12}=\frac{1}{-4}\text{and}\frac{y}{4}=\frac{1}{-4}$

$\Rightarrow x=3\text{and}y=-1$

Hence, $(3,-1)$ is a solution to the given system of equations.