Solve the given inequality for real
$x : 3 (x - 1) \leq 2 (x - 3) .$

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Solution

Solve inequality
Given, $3 (x - 1) \leq 2 (x - 3)$
$\Rightarrow 3 x - 3 \leq 2 x - 6$
$\Rightarrow 3 x - 2 x \leq - 6 + 3$
$\Rightarrow x \leq - 3$
Since $x$ is a real number less than or equal to $- 3.$
Thus, $x \in (- \infty, - 3]$

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