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Question

Solve the linear equation:
0.25(4f3)=0.05(10f9)

A
f=215
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B
f=94
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C
f=27
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D
f=35
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Solution

The correct option is D f=35
Given,0.25(4f3)=0.05(10f9)25100(4f3)=5100(10f9)25(4f3)=5(10f9)[Onmultiplyingbothsidesby100]5(4f3)=10f9[]Ondividingbothsidesby5]20f15=10f920f10f=9+15[Transposing10ftoLHSand15toRHS]10f=6f=610or35

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