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B
f=94
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C
f=27
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D
f=35
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Solution
The correct option is Df=35 Given,0.25(4f−3)=0.05(10f−9)⟹25100(4f−3)=5100(10f−9)⟹25(4f−3)=5(10f−9)[Onmultiplyingbothsidesby100]⟹5(4f−3)=10f−9[]Ondividingbothsidesby5]⟹20f−15=10f−9⟹20f−10f=−9+15[Transposing10ftoLHSand−15toRHS]⟹10f=6⟹f=610or35