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Question

Solve the pair of linear equations using cross-multiplication method.

5(x2)=4(1y)

26x+3y+4=0


A

x=2, y=13

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B

x=2, y=13

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C

x=12, y=3

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D

x=2, y=3

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Solution

The correct option is C

x=12, y=3


Consider,

5(x2)=4(1y)

4(x2)=5(1y)

4x85+5y=0

4x+5y13=0 ...(1)

Also given, 26x+3y+4=0 ...(2)


Using cross multiplication method

x5×4(3×(13))=y(13×26)(4×4)=14×3(26×5)

x20+39=y33816=112130

x20+39=112130

x=59118=12

y33816=112130

y=354118=3


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