Solve the pair of linear equations using cross-multiplication method.
5(x−2)=4(1−y)
26x+3y+4=0
x=−12, y=3
Consider,
5(x−2)=4(1−y)
4(x–2)=5(1–y)
4x–8–5+5y=0
4x+5y–13=0 ...(1)
Also given, 26x+3y+4=0 ...(2)
Using cross multiplication method
x5×4−(3×(−13))=y(−13×26)−(4×4)=14×3−(26×5)
⇒x20+39=y−338−16=112−130
⇒x20+39=112−130
⇒x=59−118=−12
⇒y−338−16=112−130
⇒y=−354−118=3