Question

A particle moves towards east with velocity 5 m/s. After 10 seconds it's direction changes towards north with same velocity. The average acceleration of the particle is.
1. $Zero$

2. $\frac{1}{\sqrt{2}}m/s^{2}N-W$

3. $\sqrt{2}m/s^{2}N-E$

4. $1m/s^{2}S-W$

Answer 1

$$a_{avg}=\frac{changeinvelocity}{changeintime}=\frac{(\overrightarrow{v_2}-\overrightarrow{v_1})}{t_2-t_1}=\frac{(5j-5i)}{10}=\frac{1}{2}\sqrt{2}=\frac{1}{\sqrt{2}}$ m/sec2 m/sec^2

aavg=12m/sec2a_{avg}=\dfrac{1}{\sqr/

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