Question

square shaped tiles of side 40cm are to be fixed in a hall of dimensions 2.4 dam by 16m.find the number of tiles required

Answer 1

Dear student
$$\begin{gathered} \mathrm{We}\mathrm{know}\mathrm{that}1\mathrm{dam}=1000\mathrm{cm} \\ \mathrm{So},2.4\mathrm{dam}=\left(2.4\times 1000\right)\mathrm{cm}=2400\mathrm{cm} \\ \mathrm{and}1\mathrm{m}=100\mathrm{cm} \\ \mathrm{So},16\mathrm{m}=\left(16\times 100\right)\mathrm{cm}=1600\mathrm{cm} \\ \mathrm{Now}\mathrm{length}\mathrm{of}\mathrm{hall},\mathrm{l}=2400\mathrm{cm} \\ \mathrm{breadth}\mathrm{of}\mathrm{hall},\mathrm{b}=1600\mathrm{cm} \\ \mathrm{Area}\mathrm{of}\mathrm{the}\mathrm{hall}=\mathrm{l}\times \mathrm{b} \\ =2400\times 1600 \\ =3840000{\mathrm{cm}}^2 \\ \mathrm{Area}\mathrm{of}\mathrm{each}\mathrm{tile},\mathrm{s}={\mathrm{s}}^2={40}^2=1600{\mathrm{cm}}^2 \\ \mathrm{So},\mathrm{number}\mathrm{of}\mathrm{tiles}\mathrm{required}=\frac{\mathrm{Area}\mathrm{of}\mathrm{the}\mathrm{hall}}{\mathrm{Area}\mathrm{of}\mathrm{each}\mathrm{tile}} \\ =\frac{3840000}{1600} \\ =2400 \end{gathered}$$
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