Standard electrode potential data are useful for understanding the suitability of an oxidant in a redox Titration. Some half – cell reactions and their standard potential are given below:
MnO−4(aq)+8H+(aq)+5e−→Mn2+(aq)+4H2O(I); E∘=1.51 V
Cr2 O2−7 (aq)+14H+(aq)+6e−→2Cr3+(aq)+7H2O(I); E∘=1.38V
Fe3+(aq)+e−→Fe2+(aq); E∘=0.77V
Cl2(g)+2e−→2Cl−(aq); E∘=1.40V
Identify the only incorrect statement regarding the quantitative estimation of aqueous Fe(NO3)2.
MnO−4 can be used in aqueous HCl
MnO−4 will oxidize Cl− into Cl2 according to the following equation:
2 MnO−4+16 H+10 Cl−→2Mn2++8 H2O+5 Cl2
The corresponding cell is
PtCl2(1 atm) |Cl−| |MnO−4,Mn2+,H+ |Pt
E∘cell=+1.51−1.40=+0.11 V
A positvie value confirms that the above process is spontaneous. Thus, MnO−4 will oxidize Cl− as well as Fe(NO3)2 simultaneously.