Standard electrode potential E o for O Cl - - Cl - and Cl - - 1 2 Cl 2 respectively 0-94V and -1-36V- The E o value for O Cl - - Cl 2 will be

The correct option is A 0.42V Cl #8722; #10230;1/2Cl2+e #8722;;Eo= #8722;1.36VCl #8722; #10230;1/2Cl2+e #8722;;Eo= #8722;1.36V ...

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Byju's Answer

Standard XII

Chemistry

Equilibrium Constant from Nernst Equation

Standard elec...

Question

Standard electrode potential $(E^{o})$ for $O {C l}^{-} / {C l}^{-}$ and ${C l}^{-} / \frac{1}{2} {C l}_{2}$ respectively $0.94 V$ and $- 1.36 V$ . The $E^{o}$ value for $O {C l}^{-} / {C l}_{2}$ will be

- 0.42 V

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- 2.20 V

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0.52 V

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1.04 V

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Solution

The correct option is A $- 0.42 V$
Cl−⟶1/2Cl2+e−;Eo=−1.36V

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Similar questions

Q. The standard electrode potentials

(E^{\circ})

for

O C l^{-} / C l^{-}

and

C l^{-} / \frac{1}{2} C l_{2}

respectively are

0.94 V

and

- 1.36 V

. The

E^{\circ}

value for

O C l^{-} / \frac{1}{2} C l_{2}

will be___________.

Q. The standard electrode potential

(E^{⊖})

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O C l^{-} | C l^{-}

and

C l^{-} | \frac{1}{2} C l_{2}

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0.94

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- 1.36

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O C l^{-} | \frac{1}{2} C l_{2}

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Q. The

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O {C l}^{-} | {C l}^{-}

and

{C l}^{-} | \frac{1}{2} {C l}_{2}

are

0.94 V

and

- 1.36 V . E

for

{O C l}^{-} | \frac{1}{2} {C l}_{2}

is:

Q. The standard reduction potentials

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for

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and for

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Q. From the standard electrode potential values of the electrodes given select an option representing their decreasing order discharge potential:

(a) A, E^{o} = 2.32 V

(b) B, E^{o} = 1.36 V

(c) C, E^{o} = 1.07 V

(c) D, E^{o} = 0.43 V

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Standard electrode potential (Eo) for OCl−/Cl− and Cl−/12Cl2 respectively 0.94V and −1.36V. The Eo value for OCl−/Cl2 will be

The correct option is A −0.42VCl−⟶1/2Cl2+e−;Eo=−1.36VCl−⟶1/2Cl2+e−;Eo=−1.36V

Standard electrode potential $(E^{o})$ for $O {C l}^{-} / {C l}^{-}$ and ${C l}^{-} / \frac{1}{2} {C l}_{2}$ respectively $0.94 V$ and $- 1.36 V$ . The $E^{o}$ value for $O {C l}^{-} / {C l}_{2}$ will be

The correct option is A $- 0.42 V$
Cl−⟶1/2Cl2+e−;Eo=−1.36V