Standard electrode potentials of three metals X,Y and Z are –1.2V,+0.5V and –3.0V respectively. The reducing power of these metals will be:
A
Y>Z>X
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B
Y>X>Z
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C
Z>X>Y
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D
X>Y>Z
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Solution
The correct option is CZ>X>Y More negative the value of stanadard reduction potential, stronger will be the reducing agent. So, Z(–3.0V)>X(–1.2V)>Y(+0.5V).