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Question

State True or False.

4y2−4y+1 = (2y−1)(2y−1)

A
True
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B
False
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Solution

The correct option is A True
We can write 4y24y+1 as
4y24y+1=(2y)22(2y)(1)+(1)2
=(2y1)2
=(2y1)(2y1)

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