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Question

Statement-1: The order of nucleophilicity in a polar-protic solvent is:I<Br<Cl<F
Statement-2: Due to its bigger size, I, it is less solvated in polar-protic solvents.

A
Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.
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B
Statement-1 is true, statement-2 is true and statement-2 is NOT correct explanation for statement-1.
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C
Statement-1 is true, statement-2 is false.
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D
Statement-1 is false, statement-2 is true.
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Solution

The correct option is D Statement-1 is false, statement-2 is true.
The decreasing order of size in polar protic solvents is as follows:
I>Br>Cl>F
Due to its greater size, I the surface charge density is low, so it is less solvated in polar protic solvent. Hence, the order of nucleophilicity will be:
I>Br>Cl>F


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