Statement-1: The order of nucleophilicity in a polar-protic solvent is:I−<Br−<Cl−<F− Statement-2: Due to its bigger size, I−, it is less solvated in polar-protic solvents.
A
Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.
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B
Statement-1 is true, statement-2 is true and statement-2 is NOT correct explanation for statement-1.
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C
Statement-1 is true, statement-2 is false.
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D
Statement-1 is false, statement-2 is true.
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Solution
The correct option is D Statement-1 is false, statement-2 is true. The decreasing order of size in polar protic solvents is as follows: I−>Br−>Cl−>F− Due to its greater size, I− the surface charge density is low, so it is less solvated in polar protic solvent. Hence, the order of nucleophilicity will be: I−>Br−>Cl−>F−