Question

Statement-1: The order of nucleophilicity in a polar-protic solvent is:$I^{-}<B{r}^{-}<C{l}^{-}<F^{-}$
Statement-2: Due to its bigger size, $I^{-}$, it is less solvated in polar-protic solvents.

• A. Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.
• B. Statement-1 is true, statement-2 is true and statement-2 is NOT correct explanation for statement-1.
• C. Statement-1 is true, statement-2 is false.
• D. Statement-1 is false, statement-2 is true.

Answer 1

The correct option is D Statement-1 is false, statement-2 is true.

The decreasing order of size in polar protic solvents is as follows:
$I^{-}>B{r}^{-}>C{l}^{-}>F^{-}$
Due to its greater size, $I^{-}$ the surface charge density is low, so it is less solvated in polar protic solvent. Hence, the order of nucleophilicity will be:
$I^{-}>B{r}^{-}>C{l}^{-}>F^{-}$