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Question

Statement I: If mcos(θ+α)=ncos(θα) then tanθ.tanα=m+nmn
Statement II: If sin(α+β)sin(αβ)=a+bab then tanα.cotβ=ab.

Which of the above statements is correct?

A
Only I
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B
Only II
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C
Both I and II
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D
Neither I nor II
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Solution

The correct option is B Only II
mcos(θ+α)=ncos(θα)cos(θ+α)cos(θα)=mn
Using componendo and dividendo, we get
cos(θ+α)+cos(θα)cos(θ+α)cos(θα)=m+nmn2cosθcosα2sinθsinα=m+nmncotθcotα=n+mnmtanθtanα=nmn+m
Hence statement I is wrong
sin(α+β)sin(αβ)=a+bab
Using componendo and dividendo, we get
sin(α+β)+sin(αβ)sin(α+β)sin(αβ)=ab2sinαcosβ2cosαsinβ=abtanαcotβ=ab
Hence statement II is true

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