Differentiation of Inverse Trigonometric Functions
Statement I: ...
Question
Statement I: If mcos(θ+α)=ncos(θ−α) then tanθ.tanα=m+nm−n Statement II: If sin(α+β)sin(α−β)=a+ba−b then tanα.cotβ=ab.
Which of the above statements is correct?
A
Only I
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B
Only II
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C
Both I and II
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D
Neither I nor II
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Solution
The correct option is B Only II mcos(θ+α)=ncos(θ−α)⇒cos(θ+α)cos(θ−α)=mn Using componendo and dividendo, we get ⇒cos(θ+α)+cos(θ−α)cos(θ+α)−cos(θ−α)=m+nm−n⇒2cosθcosα−2sinθsinα=m+nm−n⇒cotθcotα=n+mn−m⇒tanθtanα=n−mn+m Hence statement I is wrong sin(α+β)sin(α−β)=a+ba−b Using componendo and dividendo, we get ⇒sin(α+β)+sin(α−β)sin(α+β)−sin(α−β)=ab⇒2sinαcosβ2cosαsinβ=ab⇒tanαcotβ=ab Hence statement II is true