Solve this-A body of mass m collides against a wall with a velocity nbsp- -957- nbsp-and rebounds with the same speed- Its change of momentum is -a- 2 m -957- nbsp- nbsp- nbsp- nbsp- nbsp- -b- m -957- nbsp- nbsp- nbsp- nbsp- nbsp-c- -m -957- nbsp- nbsp- nbsp- nbsp- nbsp-d- Zero

Dear Student . Change in momentum will be : P= P2 P1 = mv ( mv) = 2mv nbsp; Regards ...

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Standard IX

Physics

Derivation of Position-Velocity Relation by Graphical Method

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Question

Solve this:
A body of mass m collides against a wall with a velocity $ν$ and rebounds with the same speed. Its change of momentum is :
(a) 2 m $ν$ (b) m $ν$ (c) -m $ν$ (d) Zero

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Solution

Dear Student .
Change in momentum will be :
P= P₂ -P₁ = mv - ( -mv) = 2mv
Regards

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Solve this: A body of mass m collides against a wall with a velocity ν and rebounds with the same speed. Its change of momentum is : (a) 2 mν (b) mν (c) -mν (d) Zero

Dear Student . Change in momentum will be : P= P2 -P1 = mv - ( -mv) = 2mv Regards

Solve this:
A body of mass m collides against a wall with a velocity $ν$ and rebounds with the same speed. Its change of momentum is :
(a) 2 m $ν$ (b) m $ν$ (c) -m $ν$ (d) Zero

Dear Student .
Change in momentum will be :
P= P₂ -P₁ = mv - ( -mv) = 2mv
Regards