Question

Subtract 4a^​2 + 5b + c +7 from 2a² - 6b + 4c - 10

Answer 1

Dear Student,
Here is the solution of your asked query:
$$\begin{gathered} \mathrm{Subtracting}4{\mathrm{a}}^2+5\mathrm{b}+\mathrm{c}\mathrm{from}2{\mathrm{a}}^2-6\mathrm{b}+4\mathrm{c}-10\mathrm{we}\mathrm{get}; \\ \left(2{\mathrm{a}}^2-6\mathrm{b}+4\mathrm{c}-10\right)-\left(4{\mathrm{a}}^2+5\mathrm{b}+\mathrm{c}\right) \\ =2{\mathrm{a}}^2-6\mathrm{b}+4\mathrm{c}-10-4{\mathrm{a}}^2-5\mathrm{b}-\mathrm{c} \\ =\left(2{\mathrm{a}}^2-4{\mathrm{a}}^2\right)-\left(6\mathrm{b}+5\mathrm{b}\right)+4\mathrm{c}-\mathrm{c}-10 \\ =-2{\mathrm{a}}^2-11\mathrm{b}+3\mathrm{c}-10 \end{gathered}$$
Regards