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Question

Subtract
i) 4a2bc from a+2b+3c
ii) 3x2+7y2z2from2x25y27z2

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Solution

(1)
(a+2b+3c)(4a2bc)

=a+2b+3c4a+2b+c

=a4a+2b+2b+3c+c

=5a+4b+4c

(2)
(2x25y27z2)(3x2+7y2z2)

=2x25y27z2+3x27y2+z2

=2x2+3x25y27y27z2+z2

=5x212y26z2

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