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Question

Subtract the sum of 3l − 4m − 7n2 and 2l + 3m − 4n2 from the sum of 9l + 2m − 3n2 and − 3l + m + 4n2 .....

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Solution

We have to subtract the sum of (3l - 4m - 7n2) and (2l + 3m - 4n2) from the sum of (9l + 2m - 3n2) and (-3l + m + 4n2)​

9l+2m-3n2+-3l+m+4n2-3l-4m-7n2+2l+3m-4n2
=9l-3l+2m+m-3n2+4n2-3l+2l-4m+3m-7n2-4n2
=6l+3m+n2-5l-m-11n2 (Combining like terms inside the parentheses)
=6l+3m+n2-5l+m+11n2
=6l-5l+3m+m+n2+11n2 (Collecting like terms)
=l+4m+12n2 (Combining like terms)

Thus, the required solution is l+4m+12n2.

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