Sum of two number is 42. One number is 6 more than the other number .What are the numbers?

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Solution

Let the first number be x. Then:
the second number becomes x+6
Set up an equation: x+(x+6)=42 => 2x+6=42 => 2x=42-6=> 2x=36 =>x=18 this is the first number (because this is what we set equal to x)
Second number = x+6 => 18+6=24

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Sum of two number is 42. One number is 6 more than the other number .What are the numbers?

Let the first number be x. Then: the second number becomes x+6 Set up an equation: x+(x+6)=42 => 2x+6=42 => 2x=42-6=> 2x=36 =>x=18 this is the first number (because this is what we set equal to x) Second number = x+6 => 18+6=24

Let the first number be x. Then:
the second number becomes x+6
Set up an equation: x+(x+6)=42 => 2x+6=42 => 2x=42-6=> 2x=36 =>x=18 this is the first number (because this is what we set equal to x)
Second number = x+6 => 18+6=24