Sum of two numbers is $74.$ One of the number is $10$ more than the other.what are the number.

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Solution

Let us say the other Number is x.
One of the Number is = 10+x
sum of the two Number = 74
$10 + x + x = 74$
$2 x = 74 - 10 = 64$
x = 32
& another No is 32 + 10 = 42

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Sum of two numbers is 74. One of the number is 10 more than the other.what are the number.

Let us say the other Number is x.One of the Number is = 10+xsum of the two Number = 7410+x+x=742x=74−10=64x = 32& another No is 32 + 10 = 42

Sum of two numbers is $74.$ One of the number is $10$ more than the other.what are the number.

Let us say the other Number is x.
One of the Number is = 10+x
sum of the two Number = 74
$10 + x + x = 74$
$2 x = 74 - 10 = 64$
x = 32
& another No is 32 + 10 = 42