Suppose the daily revenue (R) from selling x boxes of candy is given by the equation R = ₹ 12x. The daily cost of operating the store and the production of candy (C) is given by the equation C = ₹(8x + 96) . For how many boxes of candy will the revenue exceed the cost of production

x >24

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x< 24

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x < 18

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x > 18

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Solution

The correct option is A
x >24

For profit, revenue should exceed the cost of Production

Equation of revenue; R = 12x

Equation of cost; C = 8x + 96.

So, R $>$ C

12x $>$ (8x + 96)

x $>$ 24.

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Suppose the daily revenue from selling x boxes of candy is given by the equation R = 12x, where R is the revenue in Rs. The daily cost of operating the store and making the candy is given by the equation C = 8x + 96, where C is the making cost in Rs. For how many boxes of candy will revenue exceed making cost?

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Suppose the daily revenue (R) from selling x boxes of candy is given by the equation R = ₹ 12x. The daily cost of operating the store and the production of candy (C) is given by the equation C = ₹(8x + 96) . For how many boxes of candy will the revenue exceed the cost of production

The correct option is A x >24 For profit, revenue should exceed the cost of Production Equation of revenue; R = 12x Equation of cost; C = 8x + 96. So, R > C 12x >(8x + 96) x > 24.

The correct option is A
x >24

For profit, revenue should exceed the cost of Production

Equation of revenue; R = 12x

Equation of cost; C = 8x + 96.

So, R $>$ C

12x $>$ (8x + 96)

x $>$ 24.