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Eo for the ha...

Question

$E^{o}$ for the half cell $Z n^{2 +} /Zn$ is $- 0.76 V$ . emf of the cell $Zn/Z n^{2 +} (1M) // H^{+} (1M) / H_{2}$ at 1 atm is

- 0.76 V

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+ 0.76 V

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- 0.38 V

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+ 0.38 V

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Solution

The correct option is B $+ 0.76 V$
${E^{0}}_{c e l l} = E_{c a t h o d e} - E_{a n o d e .}$

$= E_{H^{+} / H_{2}} - E_{Z n^{2 +} Z n}$

$= 0 - (- 0.76)$

$= + 0.76$

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Similar questions

$E^{0} Z n^{2 +} / Z n = - 0.76 V$ The EMF of the cell

$Z n / Z n^{2 +} (1 M) | | H C l (p H = 2) | H_{2 (1 a t m)}, P t$ is ::

E^{o}

Z n \to Z n^{2 +} + 2 e^{-}; E^{o} = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E^{o} = + 0.41 V

F e^{2 +} + Z n \to Z n^{2 +} + F e

E^{o}

Z n ⟶ {Z n}^{2 +} + 2 e^{-}

E^{o} = + 0.76 V

F e ⟶ {F e}^{2 +} + 2 e^{-}

E^{o} = + 0.41 V

{F e}^{2 +} + Z n ⟶ {Z n}^{2 +} + F e

Z n ∣ ∣ {Z n}^{2 +} (1 M) ∣ ∣ ∣ ∣ {C u}^{2 +} (1 M) ∣ ∣ C u

E_{{C u}^{2 +} / C u}^{o} = 0.34 V

E_{{z n}^{2 +} / Z n}^{o} = - 0.76 V

E^{o}

Z n \to {Z n}^{2 +} + 2 e^{-}; E^{o} = + 0.76 V

F e \to {F e}^{2 +} + 2 e^{-}; E^{o} = + 0.41 V

{F e}^{2 +} + Z n \to {Z n}^{2 +} + F e

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