You visited us 1 times! Enjoying our articles? Unlock Full Access!

Boyle's Law

I, II, III ar...

Question

$I, II, III$ are three isotherms respectively at $T_{1}, T_{2}$ and $T_{3}$ . Temperature will be in the order:

T_{1} = T_{2} = T_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T_{1} < T_{2} < T_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T_{1} > T_{2} > T_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

T_{1} > T_{2} = T_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $T_{1} > T_{2} > T_{3}$
We know, if a horizontal line is drawn parallel to the volume axis, than at a constant pressure for every volume we get a corresponding temperature.

At constant pressure for a fixed amount of gas, volume is directly proportional to the temperature.
From graph , we know
$V_{1} > V_{2} > V_{3}$
$∴ T_{1} > T_{2} > T_{3}$

Suggest Corrections

Similar questions

T_{1}, T_{2}

T_{3}

T_{1}, T_{2}

T_{3}

T_{1}, T_{2}

T_{3}

I, II and III are three isotherms respectively at $T_{1}$ , $T_{2}$ and $T_{3}$ temperatures. The order of temperature will be

I, I I, I I I

T_{1}, T_{2}

T_{3}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program