Question

That child has age of $5$ and $20$ toys.

• A. $\frac{1}{20}$
• B. $\frac{7}{20}$
• C. $\frac{1}{25}$
• D. $\frac{1}{50}$

Answer 1

Answer: (C)

$\frac{1}{25}$

Total no. of childrens $=3+8+20+15+6+12+18+11+22+17+15+10+13+10+10+10=200$

$P\left(A\right)=\frac{\text{No. of children having age of 5 and 20 toys}}{\text{Total no. of childrens}}=\frac{8}{200}=\frac{1}{25}$