Question

That the child has age less than $10$ years and more than $20$ toys.

• A. $\frac{74}{200}$
• B. $\frac{43}{200}$
• C. $\frac{1}{4}$
• D. $\frac{39}{200}$

Answer 1

The correct option is A $\frac{74}{200}$

$P\left(Z\right)$

$=\frac{\text{no. of possible outcomes}}{\text{No. of total outcomes}}$

$=\frac{8+20+15+12+18+11}{200}$

$=\frac{74}{200}$