The 10th term of an arithmetic sequence is 65 and its 15th term is 20. Then 20th term is

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-9

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-25

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Solution

The correct option is D
-25

15th term can be obtained by adding 10th term and 5 times the common difference $(∵ 15 - 10 = 5)$

$\Rightarrow x_{15} = x_{10} + 5 d$

$\Rightarrow 20 = 65 + 5 d$

$\Rightarrow - 45 = 5 d$

$\Rightarrow d = \frac{- 45}{5} = - 9$

$\Rightarrow$ 20th term can be obtained by adding 15th term & 5 times the common difference

$\Rightarrow x_{20} = x_{15} + 5 d$

=20+5(-9)

=20-45

=-25

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