The 17th term of an AP exceeds its 10th term by 21. The common difference fo the AP is
(a) 3 (2) (c) -3 (d) -2

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Solution

Given that the 17th term of an A.P exceeds its 10th term by 7 .
d = ?
⇒a+16d = a+9d+21
⇒16d-9d = 21
⇒7d = 21
⇒d = 21/7 = 3 .
Therefore , common difference = 3 .

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