Question

The $17th$ term of an AP exceeds its $10th$ term by $7$. Find the common difference.

Answer 1

$a_n=a+(n-1)d$

$a_{17}=a+16d$

$a_{10}=a+9d$

$a_{17}=7+a_{10}$

$a_{17}-a_{10}=7$

$a+16d-a-9d=7$

$7d=7$

$d=1$