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Byju's Answer
Standard X
Chemistry
Mole Concept
The absolute ...
Question
The absolute enthalpy of neutralisation of the reaction,
M
g
O
(
s
)
+
2
H
C
l
(
a
q
.
)
→
M
g
C
l
2
(
a
q
.
)
+
H
2
O
(
l
)
will be:
A
−
57.33
k
J
m
o
l
−
1
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B
greater than
−
57.33
k
J
m
o
l
−
1
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C
less than
−
57.33
k
J
m
o
l
−
1
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D
57.33
k
J
m
o
l
−
1
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Solution
The correct option is
C
less than
−
57.33
k
J
m
o
l
−
1
The correct answer is less that
−
57.33
K
j
m
o
l
−
1
.
Because some amount the heat would be required for the ionization of the compound
M
g
O
.
Suggest Corrections
2
Similar questions
Q.
The absolute enthalpy of neutralisation of the
reaction will be:
M
g
O
(
s
)
+
2
H
C
l
(
a
q
)
→
M
g
C
l
2
(
a
q
)
+
H
2
O
(
l
)
Q.
The absolute enthalpy of neutralization of the reaction
M
g
O
(
s
)
+
2
H
C
l
(
a
q
)
→
M
g
C
l
2
(
a
q
)
+
H
2
O
(
l
)
will be:
Q.
Enthalpy of a reaction at
27
∘
C
is
15
k
J
m
o
l
−
1
The reaction will be feasible if entropy is
Q.
Given the heats of reaction below:
M
g
(
s
)
+
2
H
C
l
(
a
q
)
→
M
g
C
l
2
(
a
q
)
+
H
2
(
g
)
△
H
=
−
143
k
J
M
g
O
(
s
)
+
2
H
C
I
(
a
q
)
→
M
g
C
I
2
(
a
q
)
+
H
2
O
(
g
)
△
H
=
−
216
k
J
H
2
(
g
)
+
1
/
2
O
2
→
H
2
O
(
I
)
△
H
=
−
285
k
J
Calculate the heat for the overall reaction from the above data.
M
g
(
s
)
+
1
/
2
O
2
→
M
g
O
(
s
)
Q.
Which of the following reactions will have the value of enthalpy of neutralisation as
−
57.1
k
J
m
o
l
−
1
?
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