Question

The addition of $HBr$ to 1-butene gives a mixture of products a, b and c

The mixture consists of

• A. B as major, A and C as minor products
• B. A and B as minor and C as major products
• C. B as minor, A and C as major products
• D. A and B as major and C as minor products

Answer 1

The correct option is D

A and B as major and C as minor products

When $HBr$ is added to 1-butene, Markovnikov's rule is followed.

Thus, when $B{r}^{\Theta }$ attacks 1-butene, it will get attached to that carbon which has less number of hydrogen atoms.


The major product being optically active will exist in two structures (enantiomers):

Thus, when $HBr$ is reacted with 1-Butene, a mixture is obtained which consists of A and B as major and C as minor products.