The amount of copper (nearest integer) which can be obtained from $100$ g of anhydrous copper sulphate $(C u S O_{4})$ is :
$(C u = 63.5, S = 32, O = 16$ ) (all in amu)

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Solution

Molecular mass of $C u S O_{4} = 159.5$ g/mol. This contains $63.5$ g $C u$ .
$∴ C u$ in $100$ g $C u S O_{4} = \frac{63.5}{159.5} \times 100$ $= 39.81$ g
Therefore, the nearest integer is $40$ .

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