The amount of electrolytes required coagulate a given amount of $A g I$ colloidal solution ( $-$ ve charge) will be in the order:

N a N O_{3} > A l {(N O_{3})}_{3} > B a {(N O_{3})}_{2}

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A l {(N O_{3})}_{3} > B a {(N O_{3})}_{2} > N a N O_{3}

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A l {(N O_{3})}_{3} > N a N O_{3} > B a {(N O_{3})}_{2}

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N a N O_{3} > B a {(N O_{3})}_{2} > A l {(N O_{3})}_{3}

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Solution

The correct option is D $N a N O_{3} > B a {(N O_{3})}_{2} > A l {(N O_{3})}_{3}$
Since, $A g I$ is a negatively charged solution, so according to Hardy Schulze law, higher the positive charge on the metal atoms, more is the tendency of metal atom to cause coagulation of negatively charged colloid.

The order of positive charge is,
${N a}^{+} < {B a}^{2 +} < {A l}^{3 +}$

Thus, the order of amount of electrolytes required is in the order,
$N a N O_{3} > B a {(N O_{3})}_{2} > A l {(N O_{3})}_{3}$

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