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Byju's Answer
Standard XII
Physics
Sinusoidal Wave
The amplitude...
Question
The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is
B
0
=
510
n
T
. What is the amplitude of the electric field part of the wave?
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Solution
B
0
=
510
×
10
−
9
T
C
=
3
×
10
8
m
/
s
E
=
c
B
o
=
153
N
/
C
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Similar questions
Q.
The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is theamplitude of the electric field part of the wave?
Q.
Choose the correct answer from the alternatives given.
The amplitude of the magnetic field of a harmonic electromagnetic wave in vacuum is
B
0
=
510
n
T
.
The amplitude of the electric field aprt of the wave is:
Q.
Draw propagation diagram of a linearly polarised electromagnetic wave and write any two properties of electromagnetic waves.
The amplitude of the magnetic field associated with an electromagnetic wave in vacuum is
B
0
=
50
×
10
−
8
tesla. Write the value of amplitude of the electric field in
V
/
m
associated with the wave.
Q.
Suppose that the electric field part of an electromagnetic wave in vacuum is
E
=
(
3.1
N
/
C
)
c
o
s
[
(
1.8
r
a
d
/
m
)
y
+
(
5.4
×
10
6
r
a
d
/
s
)
t
]
^
i
(a) What is the direction of propagation?
(b) What is the wavelength
λ
?
(c) What is the frequency v?
(d) What is the amplitude of the magnetic field part of the wave?
(e) Write an expression for the magnetic field part of the wave.
Q.
The ratio of amplitude of a magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to
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