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Question

The angle between two vectors P=3^i+2^j+3^k and Q=2^i^j+3^k is:

A
cos1[577]
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B
cos1[776.5]
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C
cos1[6.577]
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D
sin1[776.5]
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Solution

The correct option is A cos1[6.577]
P=3^i+2^j+3^kQ=2^i^j+3^kPQ=θcosθ=PQPQ=3×2+2×(1)+3×332+22+3222+ (1)2+32=132214θ=cos16.577

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