The area of a rectangle is A=25a2−35a+12. Its length is (5a−3). Find its width.
5a - 3
5a - 4
4a - 5
a - 4
Let y be the width. Since area is 25a2−35a+12 , we have y(5a−3)=25a2−35a+12 ⇒ y = (25a2–35a+12)(5a−3). ∴y=5a−4
Given the area of rectangle is A=25a2−35a+69. The length is given as (5a−3).Find the width of the rectangle.
Given the area of rectangle is A=25a2−45a+18. The length is given as (5a−3). Therefore, the width is:
Given the area of a rectangle is, A=3p2+9p+6. The length is given as (3p+3). Therefore, the width is: