Question

The area of a sector (in $c{m}^2$ )of a circle with radius 6 cm if angle of the sector is ${70}^{\circ }$ will be __ $c{m}^2$. ( Take $\pi$ = $\frac{22}{7}$)

Answer 1

Given that radius r = 6 cm
$\theta$ = ${70}^{\circ }$
Area of sector of an angle $\theta$ with radius r
=$\frac{\theta }{360}$ $\times$ $\pi$ $\times$ $(r{)}^2$
= $\frac{70}{360}$ × $\frac{22}{7}$ × $6^2$
= 22 $c{m}^2$