The area of a sector with a radius of $2 c m$ is $12$ $c m^{2}$ . Calculate the angle of the sector.
(Assume $π = 3$ )

360^{o}

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160^{o}

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90^{o}

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180^{o}

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Solution

The correct option is C $360^{o}$
$r = 2$ cm
$A = 12 c m^{2}$
Area of sector $= \frac{θ}{360} \times π r^{2}$

$12 = \frac{θ}{360} \times 3 \times 2^{2}$

$θ = \frac{12 \times 360}{3 \times 4}$

$θ = 360^{o}$

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The area of a sector with a radius of 2cm is 12cm2. Calculate the angle of the sector. (Assume π=3)

The correct option is C 360or=2cmA=12cm2Area of sector =θ360×πr212=θ360×3×22θ=12×3603×4θ=360o

The area of a sector with a radius of $2 c m$ is $12$ $c m^{2}$ . Calculate the angle of the sector.
(Assume $π = 3$ )

The correct option is C $360^{o}$
$r = 2$ cm
$A = 12 c m^{2}$
Area of sector $= \frac{θ}{360} \times π r^{2}$

$12 = \frac{θ}{360} \times 3 \times 2^{2}$

$θ = \frac{12 \times 360}{3 \times 4}$

$θ = 360^{o}$